在Java中,去除数组中的重复元素是一个常见的需求,这可以通过多种方法实现,以下是一些常用的方法:

使用HashSet
HashSet是一个不允许重复元素的集合,因此可以将数组中的元素添加到HashSet中,HashSet会自动去除重复的元素,将HashSet中的元素重新放入数组中。
import java.util.HashSet;
import java.util.Arrays;
public class Main {
public static void main(String[] args) {
Integer[] array = {1, 2, 3, 4, 5, 3, 2, 1, 6, 7, 8, 7, 9, 10, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100, 101, 102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113, 114, 115, 116, 117, 118, 119, 120, 121, 122, 123, 124, 125, 126, 127, 128};
HashSet<Integer> set = new HashSet<>();
for (Integer i : array) {
set.add(i);
}
Integer[] newArray = set.toArray(new Integer[0]);
System.out.println(Arrays.toString(newArray));
}
}
使用ArrayList
ArrayList允许重复元素,但是可以通过遍历ArrayList,检查每个元素是否已经存在于ArrayList中,如果不存在,则添加到ArrayList中。
import java.util.ArrayList;
import java.util.Arrays;
public class Main {
public static void main(String[] args) {
Integer[] array = {1, 2, 3, 4, 5, 3, 2, 1, 6, 7, 8, 7, 9, 10, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100, 101, 102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113, 114, 115, 116, 117, 118, 119, 120, 121, 122, 123, 124, 125, 126, 127, 128};
ArrayList<Integer> list = new ArrayList<>();
for (Integer i : array) {
if (!list.contains(i)) {
list.add(i);
}
}
Integer[] newArray = list.toArray(new Integer[0]);
System.out.println(Arrays.toString(newArray));
}
}
使用LinkedHashSet
LinkedHashSet是一个有序的集合,它允许重复元素,但是每个元素只会出现一次,这可以通过将数组中的元素添加到LinkedHashSet中实现。

import java.util.LinkedHashSet;
import java.util.Arrays;
public class Main {
public static void main(String[] args) {
Integer[] array = {1, 2, 3, 4, 5, 3, 2, 1, 6, 7, 8, 7, 9, 10, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100, 101, 102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113, 114, 115, 116, 117, 118, 119, 120, 121, 122, 123, 124, 125, 126, 127, 128};
LinkedHashSet<Integer> set = new LinkedHashSet<>();
for (Integer i : array) {
set.add(i);
}
Integer[] newArray = set.toArray(new Integer[0]);
System.out.println(Arrays.toString(newArray));
}
}
使用排序和双指针
对于整数数组,可以先对数组进行排序,然后使用两个指针遍历数组,去除重复的元素。
import java.util.Arrays;
public class Main {
public static void main(String[] args) {
Integer[] array = {1, 2, 3, 4, 5, 3, 2, 1, 6, 7, 8, 7, 9, 10, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100, 101, 102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113, 114, 115, 116, 117, 118, 119, 120, 121, 122, 123, 124, 125, 126, 127, 128};
Arrays.sort(array);
Integer[] newArray = new Integer[array.length];
int j = 0;
for (int i = 0; i < array.length 1; i++) {
if (array[i] != array[i + 1]) {
newArray[j++] = array[i];
}
}
newArray[j++] = array[array.length 1];
System.out.println(Arrays.toString(newArray));
}
}
FAQs
Q1:Java中去除数组重复元素的最佳方法是什么?
A1:选择哪种方法取决于具体的应用场景和需求,如果数组元素类型是基本数据类型,并且需要保持元素的原始顺序,那么使用排序和双指针的方法可能更合适,如果数组元素类型是对象,或者需要去除重复的同时保持元素的插入顺序,那么使用LinkedHashSet可能更合适。

Q2:如果数组中包含大量重复元素,使用哪种方法最有效率?
A2:在这种情况下,使用HashSet可能更有效率,因为它可以快速检查元素是否已经存在于集合中,如果数组元素类型是基本数据类型,并且需要保持元素的原始顺序,那么使用排序和双指针的方法可能更有效率,因为它不需要额外的空间来存储集合。
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